- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Two cubes, each of volume $512\ cm^3$ are joined end to end. Find the surface area of the resulting cuboid.
Given:
Two cubes, each of volume $512\ cm^3$ are joined end to end.
To do:
We have to find the surface area of the resulting cuboid.
Solution:
Volume of each cube $= 512\ cm^3$
This implies,
Edge of the cube $= \sqrt[3]{512}$
$=8\ cm$
The length of the cuboid formed by joining the cubes $(l) = 8 + 8$
$= 16\ cm$
Breadth of the cuboid $(b) = 8\ cm$
Height of the cuboid $(h) = 8\ cm$
Therefore,
Surface area of the resulting cuboid $= 2(lb + bh + lh)$
$= 2(16 \times 8 + 8 \times 8 + 8 \times 16)$
$= 2(128 + 64 + 128)$
$= 2 \times 320$
$= 640\ cm^2$
Advertisements
To Continue Learning Please Login
Login with Google