Three angles of a quadrilateral are respectively equal to $110^o, 50^o$ and $40^o$. Find its fourth angle.
Given:
Three angles of a quadrilateral are respectively equal to $110^o, 50^o$ and $40^o$.
To do:
We have to find its fourth angle.
Solution:
We know that,
Sum of the angles in a quadrilateral is $360^o$.
Let the fourth angle be $x$.
Therefore,
$110^o+50^o+40^o+x=360^o$
$200^o+x=360^o$
$x=360^o-200^o$
$x=160^o$
Hence, the fourth angle is $160^o$.
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