Three $2 \mathrm{~V}$ cells are connected in series and used as a battery in a circuit.(a) What is the p.d. at the terminals of the battery?(b) How many joules of electrical energy does 1 C gain on passing through (i) one cell (ii) all three cells?

a)

Given: Three cells of 2 volt each are connected in series to make a battery

To find: Total potential difference between terminals of the battery

Solution:

Since the cells are connected in series,

Total potential difference between terminals of the battery = 2 + 2 + 2

= 6 volt

(b)

(i) one cell

When a charge Q moves between two points whose potential difference is V, the amount of work done is given by

$W = Q \times V$

Here, the electrical energy gained is nothing but work done by the battery.

$W = 1 \times 2$

$W = 2 \ joule$

So, 2 joule energy is gained by 1 coulomb of charge on passing through 1 cell.

(ii) all three cells

$W = 6 \times 1$

$W = 6 \ joule$

So, 6 joule energy is gained by 1 coulomb of charge on passing through 3 cells.

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Updated on: 10-Oct-2022

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