There are 2 oscillating pendulums:
pendulum A oscillates - 12 times in 10 secs
pendulum B oscillates - 8 times in 3 secs
Q1. Find out which pendulum has more frequency and by how much?
Q2. Find out which pendulum has more time period and by how much?

Given

In pendulum A

Oscillations - 12 times,

Time taken - 10 secs

To find, frequency and time-period

We know that,

$Frequency (f)=\frac{1}{time(t)}=\frac{no.of cycles/oscillations}{time}$

$f=\frac{12}{10}=1.2Hz$

$f=1.2Hz$

Now, the formula for time-period

$T=\frac{1}{frequency(f)}$

$T=\frac{1}{1.2}=0.83sec$

$T=0.83sec$

In pendulum B

Oscillations - 8 times

Time taken - 3 secs

We know that,

$Frequency (f)=\frac{1}{time(t)}=\frac{no.of cycles/oscillations}{time}$

$f=\frac{8}{3}=2.66Hz$

$f=2.66Hz$

Now, the formula for time-period

$T=\frac{1}{frequency(f)}$

$T=\frac{1}{2.66}=0.37sec$

$T=0.37sec$

Answer to the 1st question

Frequency of pendulum A = 1.2Hz

Frequency of pendulum B = 2.66Hz

Hence, pendulum B has more frequency than A, by 1.46Hz. (2.66 - 1.2 = 1.46)

Answer to the 2nd question

Time-period of pendulum A = 0.83sec

Time-period of pendulum B = 0.37sec

Hence, pendulum A has more time-period than B, by 0.46sec. (0.83 - 0.37 = 0.46)

Tutorialspoint

Updated on: 10-Oct-2022

16 Views

Kickstart Your Career

Get certified by completing the course

Get Started