The work done by a force $ \vec{F} $ during a displacement $ \vec{r} $ is given by $ \vec{F} \cdot \vec{r} $. Suppose a force of $ 12 \mathrm{~N} $ acts on a particle in vertically upward direction and the particle is displaced through $2.0m$ in vertically downward direction. Find the work done by the force during this displacement.

Given,

Force (F) = 12N

Displacement (s) = 2.0m

To find

Work Done (W) = ?

We know that,

$W=F\times s\times cos\Theta $

where, W = Work done,  F = Force, s = displacement, and $\Theta $= angle between the force and the direction of motion.

Substituting the value into the formula-

$W=F\times s\times cos\Theta $

$W=12\times 2.0\times cos0\unicode{xb0} $

$W=24\times 1$      $[\because cos0\unicode{xb0} =1]$

$W=24 Joule$ 

Hence, the work done by the force during this displacement is $24 J$ 

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

190 Views

Kickstart Your Career

Get certified by completing the course

Get Started