The weight of an object at the centre of the earth of radius $R$ is:
(a) zero
(b) $R$ times the weight at the surface of the earth
(c) infinite
(d) $1/R^2$ times the weight at the surface of the earth

At the center of the earth, gravitational acceleration $(g)$ is zero.

So, the weight of the object on the center of the earth $W=mg$

$=m\times 0$

$=0$

So, at the center of the earth, the weight of the object is zero.

So, option (a) is correct.

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Updated on: 10-Oct-2022

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