Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
The voltage and power of an electric bulb are 220V and 100W respectively. What will be its power when the voltage becomes 110 V?
Given:
Voltage, $V$ = 220V
Power, $P$ = 100W
To find: Power, $(P)$ when the bulb is operated on 110 V.
Solution:
We know that power is given as-
$P=\frac {V^2}{R}$
Substituting the given values we get-
$100=\frac {220^2}{R}$
$R=\frac {220\times {220}}{100}$
$R=22\times {22}$
$R=484\Omega$
Thus, the resistance of the bulb is $484\Omega$
Now,
When, the voltage, $V$ becomes 110 V, then the power consumed is given as-
$P=\frac {V^2}{R}\Rightarrow\frac {110^2}{484}\Rightarrow\frac {12100}{484}\Rightarrow25W$.
So, 25 W power is consumed when the bulb is operated on 110 V.
Updated on: 10-Oct-2022
64 Views
Advertisements