The sum of two numbers is 95. If one of the numbers exceeds other number by15 then find the numbers?

Give: The sum of two numbers is 95, one number exceeds the other by 15.

To do: Let the first number be $x$

Solution:

So, second number be $ (x+15) $

Sum of the number is  given by $ x+(x+15) = 95$

$x+x+15=95$

$2x+15 = 95$

$2x =95-15$

$2x = 80$

$x=\frac{80}{2}$

$x =40$

First number $x=40$, second number $x+15 = 40+15= 55$

The numbers are $40$ and $55$. 

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Updated on: 10-Oct-2022

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