The sum of two numbers is 48 and their product is 432. Find the numbers.

Given:

The sum of two numbers is 48 and their product is 432.

 To do:

We have to find the numbers.

Solution:

Let one of the numbers be $x$.

This implies,

The other number $=48-x$.

According to the question,

$x(48-x)=432$

$48x-x^2=432$

$x^2-48x+432=0$

Solving for $x$ by factorization method, we get,

$x^2-36x-12x+432=0$

$x(x-36)-12(x-36)=0$

$(x-36)(x-12)=0$

$x-36=0$ or $x-12=0$

$x=36$ or $x=12$

Therefore, the two numbers are $12$ and $36$.

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Updated on: 10-Oct-2022

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