The sum of three consecutive multiples of 8 is 888. Find the multiples.

Given: 

The sum of three consecutive multiples of 8 is 888.

To do:

We have to find the multiples.

Solution:

Let the three consecutive multiples of $8$ be $8x, 8x+8$ and $8x+16$

According to the given question,

$8x+ 8x+8 + 8x+16 = 888$

$24x + 24 = 888$

$24x = 888-24$

$24x = 864$

$x = \frac{864}{24}$

$x = 36$

$\Rightarrow 8x=8(36)=288$

$8x+8 = 288+8 =  296$

$8x+16 = 288+16 = 304$

Therefore, $288, 296$ and $304$ are the three multiples.

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Updated on: 10-Oct-2022

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