The sum of three consecutive multiples of 7 is 63. Find multiples.

Given :

The sum of three consecutive multiples of 7 is 63.

To do :

We have to find the numbers.

Solution :

Let the three consecutive multiples be $7x,7x+7$, and $7x+14$.

Therefore,

$7x+7x+7+7x+14=63$

$21x+21=63$

$21x=63-21$

$21x=42$

$x=\frac{42}{21}$

$x=2$

The three consecutive numbers are $7(2)=14, 7(2)+7=14+7=21, 7(2)+14=14+14=28$.

Therefore, the three numbers are 14, 21, 28.

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Updated on: 10-Oct-2022

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