The sum of the A.P. with  $21$ terms is $210$, then find the $11^{th}$ term.


Given: The sum of the A.P. with  $21$ terms is $210$.

To do: To find the $11^{th}$ term.

Solution:

Sum of $n$ terms in A.P.$=\frac{n}{2}( 2a+( n-1)d)$

$\Rightarrow 210=\frac{21}{2}(2a+20d)$

$\Rightarrow 210\times \frac{2}{21}=(2a+20d)$

$\Rightarrow \frac{420}{21}=(2a+20d)$

$\Rightarrow 20=2a+20d$

dividing both sides by $2$ we get

$10=a+10d$

We want to find the value of $11^{th}$ term

$=a+(11-1)d$

$=a+10d$

$=10$

Thus, $11^{th}$ term of the A.P. is $10$.

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Updated on: 10-Oct-2022

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