The sum of the A.P. with $21$ terms is $210$, then find the $11^{th}$ term.
Given: The sum of the A.P. with $21$ terms is $210$.
To do: To find the $11^{th}$ term.
Solution:
Sum of $n$ terms in A.P.$=\frac{n}{2}( 2a+( n-1)d)$
$\Rightarrow 210=\frac{21}{2}(2a+20d)$
$\Rightarrow 210\times \frac{2}{21}=(2a+20d)$
$\Rightarrow \frac{420}{21}=(2a+20d)$
$\Rightarrow 20=2a+20d$
dividing both sides by $2$ we get
$10=a+10d$
We want to find the value of $11^{th}$ term
$=a+(11-1)d$
$=a+10d$
$=10$
Thus, $11^{th}$ term of the A.P. is $10$.
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