The speed-time graph of an ascending passenger lift is given alongside. What is the acceleration of the lift:(i) during the first two seconds?(ii) between second and tenth second?(iii) during the last two seconds?"
(i). Acceleration during the first two seconds $=\frac{4.6-0}{2-0}=\frac{4.6}{2}=2.3\ m/s^2$
(ii). Acceleration during second and tenth seconds $=\frac{4.6-4.6}{10-2}=0$
(iii). Acceleration during last 2 seconds $=\frac{0-4.6}{12-10}$
$=\frac{-4.6}{2}$
$=-2.3\ m/s^2$ [-ve sign indicates retardation]
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