The slant height of a frustum of a cone is $4\ cm$ and the perimeter of its circular ends are $18\ cm$ and $6\ cm$. Find the curved surface area of the frustum.


Given: The slant height of a frustum of a cone is $4\ cm$ and the perimeter of its circular ends are $18\ cm$ and $6\ cm$. 

To do: To find the curved surface area of the frustum.

Solution:

As given, $l=4\ cm$

Circumference of  a circular end $=18\ cm$

$⇒2\pi r_1=18$

$⇒\pi\times r_1=\frac{18}{2}=9\ ...............................( 1)$

Circumference of other circular end $=6\ cm$

$⇒2\pi r_2=6$

$⇒\pi r_2=\frac{6}{2}=3\ .................................( 2)$

Adding $( 1)$ and $( 2)$

Curved surface area$=\pi(r_1+r_2)l$

$=( 9+3)\times4$

$=48\ cm^2$.

Tutorialspoint
Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

39 Views

Kickstart Your Career

Get certified by completing the course

Get Started
Advertisements