The refractive indexes of four substances $P,\ Q,\ R$ and $S$ are $1.77,\ 1.50,\ 2.42$ and $1.31$ respectively. When light travelling in air is incident on these substances at equal angles, the angle of refraction will be the maximum in:(a) substance P (b) substance Q (c) substance R (d) substance S
(d) substance
Explanation
The refraction or the amount of bending of light depends on the refractive index (μ) of the two media. It is calculated by $\frac {sin\ i}{sin\ r}$.
The value of (Sin i) is the same in all the cases, therefore, the value of (Sin r) will be maximum for the minimum refractive index. Hence, this implies that the angle of refraction will be maximum for minimum refractive index, and substance S has minimum refractive index, i.e 1.31.
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