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The radii of the top and bottom of a bucket of slant height $45\ cm$ are $28\ cm$ and $7\ cm$ respectively. Find the curved surface area of the bucket.
Given: The radii of the top and bottom of a bucket of slant height $45\ cm$ are $28\ cm$ and $7\ cm$ respectively.
To do: To find the curved surface area of the bucket.
Solution:
Radius of the top of the bucket $( R)=28\ cm$
Radius of the bottom of the bucket $( r)=7\ cm$
Therefore,
Curved surface area of the bucket $=\pi l( R+r)=\frac{22}{7} \times 45 ( 28+7)$
$= \frac{22}{7} \times 45 \times 35$
$ \frac{22 \times 45\times 35}{7}$
$= \frac{34650}{7}$
$= 4950\ cm^2$
Updated on: 10-Oct-2022
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