The price of 2 packets of chocolates and 3 packets of wafers is ₹ 5400. If a packet of chocolate cost ₹ 200 more than a packet of wafers, find the price of each.

Given :

The price of 2 packets of chocolates and 3 packets of wafers is Rs. 5400.

A packet of chocolates costs Rs. 200 more than a packet of wafers.

To do :

We have to find the price of each.

Solution :

Let the cost of a packet of chocolates be Rs. x and the cost of a packet of wafers be Rs. y.

This implies,

$2 \times (x) + 3 \times (y) = 5400$...........(i)

A packet of chocolates costs Rs. 200 more than a packet of wafers.

Therefore,

$x = 200+y$

Substituting $x=200+y$ in equation (i), we get,

$2 \times (200+y) + 3 \times y = 5400$

$400+2y+3y=5400$

$5y=5400-400$

$5y=5000$

$y=\frac{5000}{5}$

$y=1000$

$x=200+y$

$x=200+1000$

$x=1200$

Therefore, the price of a packet of chocolates is Rs. 1200 and the price of a packet of wafers is Rs. 1000.

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Updated on: 10-Oct-2022

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