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# The perimeter of an isosceles trapezium (having non-parallel sides equal) is 7.07 cm. If the parallel sides of the trapezium measure $\frac{37}{20}\ cm$ and $\frac{58}{25}\ cm$, find the measure of the equal non-parallel sides.

**Given:**

The perimeter of an isosceles trapezium (having non-parallel sides equal) is 7.07 cm.

The parallel sides of the trapezium measure $\frac{37}{20}\ cm$ and $\frac{58}{25}\ cm$.

**To do:**

We have to find the measure of the equal non-parallel sides.

**Solution:**

Let the length of each non-parallel side be $x\ cm$.

According to the question,

$\frac{37}{20}+\frac{58}{25}+x+x=7.07$

$1.85+2.32+2x=7.07$

$2x=7.07-4.17$

$2x=2.90$

$x=\frac{2.90}{2}$

$x=1.45\ cm$

**The measure of each of the equal non-parallel sides is 1.45 cm.**

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