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The perimeter of an isosceles trapezium (having non-parallel sides equal) is 7.07 cm. If the parallel sides of the trapezium measure $\frac{37}{20}\ cm$ and $\frac{58}{25}\ cm$, find the measure of the equal non-parallel sides.
Given:
The perimeter of an isosceles trapezium (having non-parallel sides equal) is 7.07 cm.
The parallel sides of the trapezium measure $\frac{37}{20}\ cm$ and $\frac{58}{25}\ cm$.
To do:
We have to find the measure of the equal non-parallel sides.
Solution:
Let the length of each non-parallel side be $x\ cm$.
According to the question,
$\frac{37}{20}+\frac{58}{25}+x+x=7.07$
$1.85+2.32+2x=7.07$
$2x=7.07-4.17$
$2x=2.90$
$x=\frac{2.90}{2}$
$x=1.45\ cm$
The measure of each of the equal non-parallel sides is 1.45 cm.
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