The p.d. across a $3 \Omega$ resistor is $6 \mathrm{~V}$. The current flowing in the resistor will be:(a) $\frac{1}{2} \mathrm{~A}$(b) $1 \mathrm{~A}$(c) $2 \mathrm{~A}$(d) $6 \mathrm{~A}$


Given:

Potential difference, V=6V

Resistance, R=3 ohms

To find:

Current, I

Solution:

According to the ohm's law:

$\mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}}$

$\mathrm{I}=\frac{\mathrm{6}}{\mathrm{3}}$

= 2 A

Answer is option (c)

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Updated on: 10-Oct-2022

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