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The length of a hall is 5 m more than its breadth. If the area of the floor of the hall is $84\ m^2$, what are the length and breadth of the hall?
Given:
The length of a hall is 5 m more than its breadth.
The area of the floor of the hall $=84\ m^2$.
To do:
We have to find length and breadth of the hall.
Solution:
Let the length of the rectangular hall be $x$ m and the breadth of the rectangular hall be $y$ m.
This implies,
$x=y+5\ m$
According to the question,
$x \times y=84$
$(y+5)y=84$
$y^2+5y=84$
$y^2+5y-84=0$
Solving for $y$ by factorization method, we get,
$y^2+12y-7y-84=0$
$y(y+12)-7(y+12)=0$
$(y+12)(y-7)=0$
$y+12=0$ or $y-7=0$
$y=-12$ or $y=7$
Length cannot be negative. Therefore, breadth of the hall$=7\ m$.
$x=7+5=12\ m$
The breadth of the hall is $7\ m$ and the length of the hall is $12\ m$.
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