# The length of a diagonal of a square is 8. Find the length of each side of the square.

Given:

The diagonal of a square is $8$ units.

To do:

We have to find the length of each side of the square.

Solution:

We know that,

Diagonal of a square of side $s$ is $\sqrt{2}s$.

Let the length of each side of the square be $s$.

This implies,

Diagonal of the given square $=\sqrt{2}s$.

Therefore,

$8=\sqrt{2}s$

$s=\frac{4\times2}{\sqrt2}$

$s=\frac{4\times\sqrt2\times\sqrt2}{\sqrt2}$

$s=4\sqrt2$

The length of each side of the square is $4\sqrt2$ units.

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