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The integer $-3$ exceeds $-5$ by how much?
Given :
The given numbers are $-3$ and $-5$.
To do :
We have to find how much $-3$ exceeds $-5$ by.
Solution :
To find how much $-3$ exceeds $-5$ by we have to subtract $-5$ from $-3$.
$-3-(-5) = -3+5$ $[ - x - = + ]$
$= 5-3$
$= 2$
Therefore, $-3$ exceeds $-5$ by 2.
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