The following is the distribution of height of students of a certain class in a certain city:
Height (in cms): | 160-162 | 163-165 | 166-168 | 169-171 | 172-174 |
No. of students: | 15 | 118 | 142 | 127 | 18 |
Find the average height of maximum number of students.
Given:
The distribution of height of students of a certain class in a certain city.
To do:
We have to find the average height of maximum number of students.
Solution:
The frequency of the given data is as given below.
Height (in cms) $x_i$: | No. of students $f_i$: |
160-162
| 15 |
163-165
| 118 |
166-168
| 142 |
169-171
| 127 |
172-174
| 18 |
We observe that the class interval of 166-168 has the maximum frequency(142).
Therefore, it is the modal class.
Here,
$l=166, h=2, f=142, f_1=118, f_2=127$
We know that,
Mode $=l+\frac{f-f_1}{2 f-f_1-f_2} \times h$
$=166+\frac{142-118}{2 \times 142-118-127} \times 2$
$=166+\frac{24}{284-245} \times 2$
$=166+\frac{48}{39}$
$=166+1.3$
$=167.3$
Hence, the average height of maximum number of students is 167.3 cm.
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