The following is the cumulative frequency distribution (of less than type) of 1000 persons each of age 20 years and above. Determine the mean age.

Age below (in years):	30	40	50	60	70	80
Number of persons:	100	220	350	750	950	1000.

Given:

The cumulative frequency distribution (of less than type) of 1000 persons each of age 20 years and above.

To do:

We have to find the mean age.

Solution:

First,  make the frequency distribution of the given data and then proceed to calculate the mean as follows:

Let the assumed mean be $A=45$.

Class size $h=10$

Mean $=A+h \times \frac{\sum{f_iu_i}}{\sum{f_i}}$    

Therefore,  

Mean $=45+10\times(\frac{630}{1000})$

$=45+6.3$

$=51.3$

The age is 51.3 years. 

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Updated on: 10-Oct-2022

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