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The following distribution gives the number of accidents met by 160 workers in a factory during a month.
| No. of accidents ($x$): | 0 | 1 | 2 | 3 | 4 |
| No. of workers ($f$): | 70 | 52 | 34 | 3 | 1 |
Given:
The number of accidents met by 160 workers in a factory during a month.
To do:
We have to find the average number of accidents per worker.
Solution:
Let the assumed mean be $A=2$
| Number of accidents ($x_i$) | Number of workers ($f_i$) | $d = x_i -A$ $A = 2$ | $f_i \times\ d_i$ |
| 0 | 70 | $-2$ | $-140$ |
| 1 | 52 | $-1$ | $-52$ |
| 2-$A$ | 34 | 0 | 0 |
| 3 | 3 | 1 | 3 |
| 4 | 1 | 2 | 2 |
| Total | $\sum{f_i}=160$ | $\sum{f_id_i}=-187$ |
We know that,
Mean $=A+\frac{\sum{f_id_i}}{\sum{f_i}}$
Therefore,
Mean $=2+\frac{-187}{160}$
$=2-1.17$
$=0.83$
The average number of accidents per worker is $0.83$.
Updated on: 10-Oct-2022
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