The difference between two numbers is 26 and one number is three times the other. Find them.

Given:

The difference between two numbers is 26 and one number is three times the other.

 To do:

We have to find the number.

Solution:

Let the numbers be $x$ and $y$.

According to the question,

$x-y=26$

$x=y+26$....(i)

One number is three times the other.

This implies,

$x=3y$     ($x$ is the larger number as $x-y=26$)

Substituting $x=3y$ in equation (i), we get,

$3y=y+26$

$3y-y=26$

$2y=26$

$y=13$

Therefore,

$x=3y=3(13)=39$

The required numbers are 13 and 39. 

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Updated on: 10-Oct-2022

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