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The diameters of the lower and upper ends of a bucket in the form of a frustum f a cone are $10\ cm$ and $30\ cm$ respectively. If its height is $24\ cm$, find:
$( i)$ The area of the metal sheet used to make the bucket.
$( ii)$ Why we should avoid the bucket made by ordinary plastic? [Use $\pi=3.14$ ]
Given: The diameters of the lower and upper ends of a bucket in the form of a frustum of a cone are $10\ cm$ and $30\ cm$ respectively. height of the cone $=24\ cm$
To do: To find:
$( i)$ The area of the metal sheet used to make the bucket.
$( ii)$ Why we should avoid the bucket made by ordinary plastic? [Use $\pi=3.14$ ]
Solution:
$\because$ Diameters of the lower and the upper ends are $10\ cm$ and $30\ cm$.$\therefore$ Radius of the lower end, $r=\frac{10}{2}=5\ cm$
Radius of the upper end, $R=\frac{30}{2}=15\ cm$
Height of the cone, $h=24\ cm$
Let $l$ is the slant height of the cone,
As known, $l^{2}=h^{2}+( R-r)^{2}$
$\Rightarrow l^{2}=(24)^{2}+( 15-5)^{2}$
$\Rightarrow l^{2}=576+100=676$
$\Rightarrow l=\sqrt{676}=26\ cm$
$( i)$ Required Area of the metal sheet$=\pi [r^{2}+( r+R)l]$
$=3.14[5^{2}+( 5+15)26]$
$3.14[25+520]$
$3.14\times545$
$1711.3\ cm^{2}$.
$( ii)$ Plastic is very harmful to the environment, so to keep our environment safe its use should be avoided.
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