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The diagonals of rhombus are $20\ cm$ and $48\ cm$ respectively, then find the side of the rhombus.
Given: The diagonals of rhombus are $20\ cm$ and $48\ cm$ respectively
To do: To find the side of the rhombus.
Solution:
As given diagonals of rhombus are $20\ cm$ and $48\ cm$.
Semi diagonals are $\frac{20}{2}=10\ cm$ and $\frac{48}{2}=24\ cm$
Side of rhombus is as hypotenuse of semi diagonals i.e.,
$Side^2=10^2+24^2$ [Using pythagoras theorem]
$\Rightarrow side=\sqrt{100+576}$
$=\sqrt{676}$
$=26\ cm$
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