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The diagonal of a square is 4√2 then, find the following.
A. Length of each side
B. Perimeter of the square
Given:
The diagonal of a square is $4\sqrt2$ units.
To do:
We have to find
A. Length of each side
B. Perimeter of the square
Solution:
We know that,
Diagonal of a square of side $s$ is $\sqrt{2}s$.
Perimeter of a square of side $s$ is $4s$.
Let the length of each side of the square be $s$.
A. Diagonal of the square $=\sqrt{2}s$.
Therefore,
$4\sqrt{2}=\sqrt{2}s$
$s=4$
Length of the side of the square is $4$ units.
B. Perimeter of the square $=4s$
$=4(4)$
$=16$ units.
The perimeter of the square is $16$ units.
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