# The diagonal of a square is 4âˆš2Â  then, find the following.A. Length of each side B. Perimeter of the square

Given:

The diagonal of a square is $4\sqrt2$ units.
To do:

We have to find

A. Length of each side

B. Perimeter of the square

Solution:

We know that,

Diagonal of a square of side $s$ is $\sqrt{2}s$.

Perimeter of a square of side $s$ is $4s$.

Let the length of each side of the square be $s$.

A. Diagonal of the square $=\sqrt{2}s$.

Therefore,

$4\sqrt{2}=\sqrt{2}s$

$s=4$

Length of the side of the square is $4$ units.

B. Perimeter of the square $=4s$

$=4(4)$

$=16$ units.

The perimeter of the square is $16$ units.

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