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# The diagonal of a square is 4âˆš2Â then, find the following.

A. Length of each side

B. Perimeter of the square

**Given:**

The diagonal of a square is $4\sqrt2$ units.

To do:

We have to find

A. Length of each side

B. Perimeter of the square

**Solution:**

We know that,

Diagonal of a square of side $s$ is $\sqrt{2}s$.

Perimeter of a square of side $s$ is $4s$.

Let the length of each side of the square be $s$.

A. Diagonal of the square $=\sqrt{2}s$.

Therefore,

$4\sqrt{2}=\sqrt{2}s$

$s=4$

**Length of the side of the square is $4$ units.**

B. Perimeter of the square $=4s$

$=4(4)$

$=16$ units.

**The perimeter of the square is $16$ units.**

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