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The curved surface area of a cone is $4070\ cm^2$ and its diameter is $70\ cm$. What is the slant height? (Use $\pi = \frac{22}{7}$).
Given:
The curved surface area of a cone is $4070\ cm^2$ and its diameter is $70\ cm$.
To do:
We have to find the slant height.
Solution:
Surface area of the cone $= 4070\ cm^2$
Diameter of the base $= 70\ cm$
This implies,
Radius of the base $(r)=\frac{70}{2}$
$=35 \mathrm{~cm}$
Therefore,
The slant height of the cone $=\frac{\text { Surface area }}{\pi r}$
$=\frac{4070 \times 7}{22 \times 35}$
$=37 \mathrm{~cm}$
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