The current flowing through a resistor connected in a circuit and the potential difference developed across its ends are as shown in the diagram by milliammeter and voltmeter readings respectively:
(a) What are the least counts of these meters?
(b) What is the resistance of the resistor?
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(a) Least count of ammeter = $10mA$ $(\because one\ marking\ or\ line\ denotes\ the\ value\ 10)$
Least count of voltmeter = $0.1V$ $(\because one\ marking\ or\ line\ denotes\ the\ value\ 0.1)$
(b) Given:
Reading of ammeter, $I=200+(5\times 10)=200+50=250mA=\frac {250}{1000}A=0.25A$
Reading of voltmeter, $V=2+(4\times 0.1)=2+0.4=2.4V$
To find: Resistance of the resistor, $R$.
Solution:
We know that, resistance is given as-
$R=\frac {V}{I}$
Putting the given values, we get-
$R=\frac {2.4}{0.25}$
$R=\frac {24\times 100}{25\times 10}$
$R=\frac {240}{25}$
$R=9.6\Omega$
Thus, the resistance of the resistor, $R$ is 9.6 Ohm.
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