The co-ordinates of the point P are $(-3,2)$. Find the coordinates of the point Q which lies on the line joining P and origin such that $OP = OQ$.
Given:
The co-ordinates of the point P are $(-3,2)$.
To do:
We have to find the coordinates of the point Q which lies on the line joining P and origin such that $OP = OQ$.
Solution:
Co-ordinates of $P$ are $(-3, 2)$ and origin $O$ are $(0, 0)$.
Let the co-ordinates of $Q$ be $(x, y)$
$O$ is the mid-point of $PQ$
This implies,
$OP=OQ$
By mid-point theorem,
$\frac{-3+x}{2}=0$ and $\frac{2+y}{2}=0$
$\Rightarrow -3+x=0$ and $2+y=0$
$\Rightarrow x=3$ and $y=-2$
Therefore, the coordinates of the point $Q$ are $(3, -2)$.
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