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The circumference of lower and upper bases of the frustum cone is $250\ cm$ and $120\ cm$. The slant height is $12\ cm$. Find the curved surface area.
Given: The circumference of lower and upper bases of the frustum cone is $250\ cm$ and $120\ cm$. The slant height is $12\ cm$.
To do: To find the curved surface area.
Solution:
As given, circumference of the lower end $=2\pi R=250\ cm$
Circumference of the upper end $=2\pi r=120\ cm$
Curved surface area of the frustum cone $=\frac{1}{2}( 2\pi R+2\pi r)l$
$=\frac{1}{2}(250+120)\times12$
$=370\times6$
$=2,220\ cm^2$
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