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The breadth of a room is twice its height, one half of its length and the volume of the room is $512$ cu. dm. Find its dimensions.
Given:
The breadth of a room is twice its height, one half of its length and the volume of the room is $512$ cu. dm.
To do:
We have to find its dimensions.
Solution:
Let the breadth of the room be $(b) = x$
This implies,
Height of the room $(h)=\frac{x}{2}$
Length of the room $(l)=2 x$
Therefore,
Volume of the room $=l b h$
$=x \times \frac{x}{2} \times 2 x$
$=x^{3}$
$x^{3}=512$
$=(8)^{3}$
$\Rightarrow x=8$
This implies,
Length $=2 x$
$=2 \times 8$
$=16 \mathrm{dm}$
Breadth $=x$
$=8 \mathrm{dm}$
Height $=\frac{x}{2}$
$=\frac{8}{2}$
$=4 \mathrm{dm}$
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