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The areas of two similar triangles $ABC$ and $PQR$ are in the ratio $9:16$. If $BC=4.5\ cm$, find the length of $QR$.
Given:
The areas of two similar triangles $ABC$ and $PQR$ are in the ratio $9:16$ and $BC=4.5\ cm$.
To do:
We have to find the length of $QR$.
Solution:
We know that,
If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides.
Therefore,
$\frac{ar(\triangle ABC)}{ar(\triangle PQR)}=\frac{(BC)^2}{(QR)^2}$
$\frac{9}{16}=(\frac{4.5}{QR})^2$
$\frac{4.5}{QR}=\sqrt{\frac{9}{16}}$
$\frac{4.5}{QR}=\frac{3}{4}$
$4.5(4)=3(QR)$
$QR=\frac{18}{3}$
$QR=6\ cm$
The length of $QR$ is $6\ cm$.
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