The area of the triangle formed by \( x+y=10 \) and the coordinate axis is
(A) \( 50 \mathrm{sq} \). units
(B) 25 sq. units
(C) \( 40 \mathrm{sq} \). units
(D) none of these

Given:

\( x+y=10 \) meets the coordinate axis and forms a triangle with it.

To do:

We have to find the area of the triangle so formed.

Solution:

Let \( x+y=10 \) meets the X-axis at $A(a, 0)$ and Y-axis at $B(0, b)$.
This implies,

$(a)+0=10$

$a=10$

$0+(b)=10$

$b=10$

Area of the triangle $=\frac{1}{2}\times10\times10$

$=50$ sq. units.

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Updated on: 10-Oct-2022

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