The area of the triangle formed by $ x+y=10 $ and the coordinate axis is
(A) $ 50 \mathrm{sq} $. units
(B) 25 sq. units
(C) $ 40 \mathrm{sq} $. units
(D) none of these
Given:
\( x+y=10 \) meets the coordinate axis and forms a triangle with it.
To do:
We have to find the area of the triangle so formed.
Solution:
Let \( x+y=10 \) meets the X-axis at $A(a, 0)$ and Y-axis at $B(0, b)$.
This implies,
$(a)+0=10$
$a=10$
$0+(b)=10$
$b=10$
Area of the triangle $=\frac{1}{2}\times10\times10$
$=50$ sq. units.
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