The area of rhombus whose diagonals are of lengths $ 10 \mathrm{~cm} $ and $ 8.2 \mathrm{~cm} $ is____
$41\ cm^2$
$82\ cm^2$$410\ cm^2$
$820\ cm^2$

Given:

The diagonals of a rhombus are \( 10 \mathrm{~cm} \) and \( 8.2 \mathrm{~cm} \).
To do:

We have to find the area of the rhombus.
Solution:
We know that,

Area of a rhombus of diagonals of length $d_1$ and $d_2$ is $\frac{1}{2}\times d_1 \times d_2$.

Therefore,

The area of the given rhombus$=\frac{1}{2}\times10\times8.2\ cm^2$

$=\frac{82}{2}\ cm^2$

$=41\ cm^2$

Therefore, the area of the rhombus is $41\ cm^2$.

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Updated on: 10-Oct-2022

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