The annual rate of growth in the population of a certain city is 8% if it's present population is 196380. What was it 3 years ago?

Given:

The annual rate of growth in the population of a certain city is 8%.

The present population of the city is 196380. 
 

To do:

We have to find the population of the city 3 years ago.

Solution:

Let the population of the city 3 years ago be x.

This implies,

$x(1+\frac{8}{100})^3=196380$

$x(\frac{108}{100})^3=196380$

$x=196380\times(\frac{25}{27})^3$

$x=10\times15625$

$x=156250$

The population 3 years ago was 156250.

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Updated on: 10-Oct-2022

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