Subtract x²-y²+z² from x²-y²- z²

To do:

We have to subtract $x^2-y^2+z^2$ from $x^2-y^2- z^2$.

Solution:

$(x^2-y^2- z^2)-(x^2-y^2+z^2)=(x^2-x^2)+(-y^2+y^2)+(-z^2-z^2)$

$=0+0-2z^2$

$=-2z^2$

Therefore, $(x^2-y^2- z^2)-(x^2-y^2+z^2)=-2z^2$.

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Updated on: 10-Oct-2022

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