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Subtract x²-y²+z² from x²-y²- z²
To do:
We have to subtract $x^2-y^2+z^2$ from $x^2-y^2- z^2$.
Solution:
$(x^2-y^2- z^2)-(x^2-y^2+z^2)=(x^2-x^2)+(-y^2+y^2)+(-z^2-z^2)$
$=0+0-2z^2$
$=-2z^2$
Therefore, $(x^2-y^2- z^2)-(x^2-y^2+z^2)=-2z^2$.
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