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Subtract the following:(a) $9$ from $(-6)$(b) $(-8)$ from $8$(c) $6$ from $0$.
Given :
The given terms are
(a) $9$ from $(-6)$
(b) $(-8)$ from $8$
(c) $6$ from $0$.
To do :
We have to subtract the given erms.
Solution :
We know that,
$(+) \times (+) = (+) = (-) \times (-)$
$(+) \times (-) = (-) = (-) \times (+)$
a. $(-6) - 9 = -(6+9) = -15$.
b. $8-(-8) = 8+8 = 16$.
c. $0-6= -(6-0)= -6$.
Updated on: 10-Oct-2022
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