Subtract $ 4 p^{2} q-3 p q+5 p q^{2}-8 p+7 q-10 $ from $ 18-3 p-11 q+5 p q-2 p q^{2}+5 p^{2} q $.

Given:

Given expessions are \( 4 p^{2} q-3 p q+5 p q^{2}-8 p+7 q-10 \) and \( 18-3 p-11 q+5 p q-2 p q^{2}+5 p^{2} q \).
To do:

We have to subtract \( 4 p^{2} q-3 p q+5 p q^{2}-8 p+7 q-10 \) from \( 18-3 p-11 q+5 p q-2 p q^{2}+5 p^{2} q \).

Solution:

$(18-3p-11q+5pq-2pq^{2}+5p^{2}q)-(4p^{2}q-3pq+5pq^{2}-8p+7q-10)=(5-4)p^2q+(-2-5)pq^2+(5+3)pq+(-3+8)p+(-11-7)q+(18+10)$

$=p^2q-7pq^2+8pq+5p-18q+28$.

Therefore, the answer is $p^2q-7pq^2+8pq+5p-18q+28$.

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Updated on: 10-Oct-2022

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