Solve the pair of linear equations:

3x $+$ 2y = 4

4x $+$ 6y = 2

Given: 3x $+$ 2y = 4   ...(i)

             4x $+$ 6y = 2   ...(ii)

To find: We have to find x from the given equations.

Solution: 

Multiplying eq (i) with 3:

$3( 3x\ +\ 2y) \ =\ 3( 4)$

$9x\ +\ 6y\ =\ 12$      ...(iii)

Subtracting eq (ii) from eq (iii)

$9x\ +\ 6y\ -\ ( 4x\ +\ 6y) \ =\ 12\ -\ 2$

$9x\ +\ 6y\ -\ 4x\ -\ 6y\ =\ 12\ -\ 2$

$5x\ \ =\ 10$

$x\ \ =\ \frac{10}{5}$

$x\ =\ 2$

Putting value of x in eq (i)

3(2) $+$ 2y = 4  

6 $+$ 2y = 4  

2y = 4 $-$ 6 

2y = $-$ 2

y = $-$ $\frac{2}{2}$

y = $-$1

So, solution to the given equations is x=2 and y=$-$1.