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Solve the pair of linear equation: $2x+y=5\ .......\ ( i)$$3x+2y=8\ .......\ ( ii)$
Given: Pair of linear equations: $2x+y=5\ .....\ ( i)$ $3x+2y=8\ .....\ ( ii)$
To do: To solve the given pair of linear equation.
Solution:
$2x+y=5\ .....\ ( i)$
$3x+2y=8\ .....\ ( ii)$
Let us multiply $( i)$ by $2$, it becomes:
$4x+2y=10\ .....\ ( iii)$
On subtracting $( ii)$ from $( iii)$ we have:
$4x+2y-( 3x+2y)=10-8$
$\Rightarrow 4x+2y-3x-2y=2$
$\Rightarrow x=2$, let's put this value in $( i)$
$2( 2)+y=5$
$\Rightarrow 4+y=5$
$\Rightarrow y=5-4$
$\Rightarrow y=1$
Thus, $x=2,\ y=1$
Updated on: 10-Oct-2022
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