Solve the following system of equations graphically:
$x\ +\ y\ =\ 3$
$2x\ +\ 5y\ =\ 12$


Given:

The given system of equations is:


$x\ +\ y\ =\ 3$


$2x\ +\ 5y\ =\ 12$

 

To do:

We have to represent the above system of equations graphically.


Solution:

The given pair of equations are:

$x\ +\ y\ -\ 3\ =\ 0$....(i)

$y=3-x$

$2x\ +\ 5y\ -\ 12\ =\ 0$....(ii)

$5y=12-2x$

$y=\frac{12-2x}{5}$

To represent the above equations graphically we need at least two solutions for each of the equations.

For equation (i),

If $x=0$ then $y=3-0=3$

If $y=0$ then $0=3-x$

$x=3$

$x$$0$$3$

$y=3-x$

$3$$0$

For equation (ii),

If $x=0$ then $y=\frac{12-2(0)}{5}=\frac{12}{5}$ which is not an integer and so it is difficult to locate on the graph.

If $x=1$ then $y=\frac{12-2(1)}{5}=\frac{12-2}{5}=\frac{10}{5}=2$

If $x=-4$ then $y=\frac{12-2(-4)}{5}=\frac{12+8}{5}=\frac{20}{5}=4$

$x$$1$$-4$
$y=\frac{12-2x}{5}$$2$$4$

The above situation can be plotted graphically as below:


The line AB represents the equation $x+y-3=0$ and the line PQ represents the equation $2x+5y-12=0$.

The solution of the given system of equations is the intersecting point of both the lines.

Hence, the solution of the given system of equations is $x=1$ and $y=2$.

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Updated on: 10-Oct-2022

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