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Solve the following quadratic equation by factorization:
$x^2+2ab=(2a+b)x$
Given:
Given quadratic equation is $x^2+2ab=(2a+b)x$.
To do:
We have to solve the given quadratic equation.
Solution:
$x^2+2ab=(2a+b)x$
$x^2-(2a+b)x+2ab=0$
$x^2-2ax-bx+2ab=0$
$x(x-2a)-b(x-2a)=0$
$(x-b)(x-2a)=0$
$x-b=$ or $x-2a=0$
$x=b$ or $x=2a$
The values of $x$ are $2a$ and $b$.
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