Solve the following quadratic equation by factorization:

$x^2+2ab=(2a+b)x$

Given:

Given quadratic equation is $x^2+2ab=(2a+b)x$.

To do:

We have to solve the given quadratic equation.

Solution:

 

$x^2+2ab=(2a+b)x$

$x^2-(2a+b)x+2ab=0$

$x^2-2ax-bx+2ab=0$

$x(x-2a)-b(x-2a)=0$

$(x-b)(x-2a)=0$

$x-b=$ or $x-2a=0$

$x=b$ or $x=2a$

The values of $x$ are $2a$ and $b$.