Solve the following quadratic equation by factorization:

$x^2-(\sqrt3+1)x+\sqrt3=0$

Given:

Given quadratic equation is $x^2-(\sqrt3+1)x+\sqrt3=0$.

To do:

We have to solve the given quadratic equation.

Solution:

$x^2-(\sqrt3+1)x+\sqrt3=0$

$x^2-\sqrt{3}x-x+\sqrt3=0$

$x(x-\sqrt3)-1(x-\sqrt3)=0$

$(x-1)(x-\sqrt3)=0$

$x-1=0$ or $x-\sqrt3=0$

$x=1$ or $x=\sqrt3$

The values of $x$ are $1$ and $\sqrt3$.

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Updated on: 10-Oct-2022

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