Solve the following quadratic equation by factorization:
$2x^2\ +\ ax\ –\ a^2\ =\ 0$

Given:

Given quadratic equation is $2x^2\ +\ ax\ –\ a^2\ =\ 0$.

To do:

We have to solve the given quadratic equation by factorization. 

Solution:

$2x^2+ax-a^2=0$

$2x^2+2ax-ax-a^2=0$

$2x(x+a)-a(x+a)=0$

$(2x-a)(x+a)=0$

$2x-a=0$ or $x+a=0$

$2x=a$ or $x=-a$

$x=\frac{a}{2}$ or $x=-a$

The roots of the given quadratic equation are $\frac{a}{2}$ and $-a$.  

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Updated on: 10-Oct-2022

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