Solve the following pair of linear equations by substitution method:
$ x+y=5 $ and $ 2 x-3 y=4 $


Given:

Given pair of equations is:

\( x+y=5 \) and \( 2 x-3 y=4 \)

To do:

We have to solve the given pair of equations by substitution method.

Solution:

$x+y=5$

This implies,

$x=5-y$.....(i)

$2x-3y=4$

$2(5-y)-3y=4$            [From (i)] $2(5)-2(y)-3y=4$

$10-2y-3y=4$

$10-4=5y$

$5y=6$

$y=\frac{6}{5}$

Therefore,

$x=5-\frac{6}{5}$

$x=\frac{5\times5-6}{5}$

$x=\frac{25-6}{5}$

$x=\frac{19}{5}$

The values of $x$ and $y$ are $\frac{19}{5}$ and $\frac{6}{5}$ respectively.

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Updated on: 10-Oct-2022

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