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Solve the following$t – (2t + 5) – 5(1 – 2t) = 2(3 + 4t) – 3(t -4)$
Given:
$t-(2t+5)-5(1-2t)=2(3+4t)-3(t-4)$
To do: Solve the given expression.
Solution:
We have to expand the brackets and find value of t
=> $t - 2t - 5 - 5 + 10t = 6 + 8t - 3t + 12$
=> $t - 2t + 10t - 8t + 3t = 6 + 12 + 5 + 5$
=> $(1-2+10-8+3)t = 28$
=> $4t = 28$
Divide each term by 4 , we get
=> $t = 7$
Therefore, value of t = 7
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