Solve the following:$\frac{3y+4}{2-6y}=\frac{-2}{5}$.

Given :

The given expression is $\frac{3y+4}{2-6y}=\frac{-2}{5}$.

To do :

We have to find the value of y.

Solution :

On cross multiplication,

$\frac{3y+4}{2-6y}=\frac{-2}{5}$

$(3y+4)5 = -2(2-6y)$

$15y+20=-4+12y$

$15y - 12y = -4-20$

$3y = -24$

$y= \frac{-24}{3}$

$y = -8$

Therefore, the value of y is $-8$.

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

24 Views

Kickstart Your Career

Get certified by completing the course

Get Started